(3x^2-6x+3)/(x^2-1)^2

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Solution for (3x^2-6x+3)/(x^2-1)^2 equation: 


D( x )

(x^2-1)^2 = 0

(x^2-1)^2 = 0

(x^2-1)^2 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

(3*x^2-(6*x)+3)/((x^2-1)^2) = 0

(3*x^2-6*x+3)/((x^2-1)^2) = 0

3*x^2-6*x+3 = 0

3*(x^2-2*x+1) = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

3*(x-1)^2 = 0

(3*(x-1)^2)/((x^2-1)^2) = 0

x-1 = 0 // + 1

x = 1

x in { 1} 

x belongs to the empty set

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